Optimal. Leaf size=98 \[ -\frac {1}{d^2 \left (b^2-4 a c\right ) (b+2 c x) \left (a+b x+c x^2\right )}-\frac {12 c}{d^2 \left (b^2-4 a c\right )^2 (b+2 c x)}+\frac {12 c \tanh ^{-1}\left (\frac {b+2 c x}{\sqrt {b^2-4 a c}}\right )}{d^2 \left (b^2-4 a c\right )^{5/2}} \]
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Rubi [A] time = 0.06, antiderivative size = 98, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {687, 693, 618, 206} \begin {gather*} -\frac {1}{d^2 \left (b^2-4 a c\right ) (b+2 c x) \left (a+b x+c x^2\right )}-\frac {12 c}{d^2 \left (b^2-4 a c\right )^2 (b+2 c x)}+\frac {12 c \tanh ^{-1}\left (\frac {b+2 c x}{\sqrt {b^2-4 a c}}\right )}{d^2 \left (b^2-4 a c\right )^{5/2}} \end {gather*}
Antiderivative was successfully verified.
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Rule 206
Rule 618
Rule 687
Rule 693
Rubi steps
\begin {align*} \int \frac {1}{(b d+2 c d x)^2 \left (a+b x+c x^2\right )^2} \, dx &=-\frac {1}{\left (b^2-4 a c\right ) d^2 (b+2 c x) \left (a+b x+c x^2\right )}-\frac {(6 c) \int \frac {1}{(b d+2 c d x)^2 \left (a+b x+c x^2\right )} \, dx}{b^2-4 a c}\\ &=-\frac {12 c}{\left (b^2-4 a c\right )^2 d^2 (b+2 c x)}-\frac {1}{\left (b^2-4 a c\right ) d^2 (b+2 c x) \left (a+b x+c x^2\right )}-\frac {(6 c) \int \frac {1}{a+b x+c x^2} \, dx}{\left (b^2-4 a c\right )^2 d^2}\\ &=-\frac {12 c}{\left (b^2-4 a c\right )^2 d^2 (b+2 c x)}-\frac {1}{\left (b^2-4 a c\right ) d^2 (b+2 c x) \left (a+b x+c x^2\right )}+\frac {(12 c) \operatorname {Subst}\left (\int \frac {1}{b^2-4 a c-x^2} \, dx,x,b+2 c x\right )}{\left (b^2-4 a c\right )^2 d^2}\\ &=-\frac {12 c}{\left (b^2-4 a c\right )^2 d^2 (b+2 c x)}-\frac {1}{\left (b^2-4 a c\right ) d^2 (b+2 c x) \left (a+b x+c x^2\right )}+\frac {12 c \tanh ^{-1}\left (\frac {b+2 c x}{\sqrt {b^2-4 a c}}\right )}{\left (b^2-4 a c\right )^{5/2} d^2}\\ \end {align*}
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Mathematica [A] time = 0.12, size = 84, normalized size = 0.86 \begin {gather*} -\frac {\frac {12 c \tan ^{-1}\left (\frac {b+2 c x}{\sqrt {4 a c-b^2}}\right )}{\sqrt {4 a c-b^2}}+\frac {b+2 c x}{a+x (b+c x)}+\frac {8 c}{b+2 c x}}{d^2 \left (b^2-4 a c\right )^2} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [F] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{(b d+2 c d x)^2 \left (a+b x+c x^2\right )^2} \, dx \end {gather*}
Verification is not applicable to the result.
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fricas [B] time = 0.42, size = 644, normalized size = 6.57 \begin {gather*} \left [-\frac {b^{4} + 4 \, a b^{2} c - 32 \, a^{2} c^{2} + 12 \, {\left (b^{2} c^{2} - 4 \, a c^{3}\right )} x^{2} - 6 \, {\left (2 \, c^{3} x^{3} + 3 \, b c^{2} x^{2} + a b c + {\left (b^{2} c + 2 \, a c^{2}\right )} x\right )} \sqrt {b^{2} - 4 \, a c} \log \left (\frac {2 \, c^{2} x^{2} + 2 \, b c x + b^{2} - 2 \, a c + \sqrt {b^{2} - 4 \, a c} {\left (2 \, c x + b\right )}}{c x^{2} + b x + a}\right ) + 12 \, {\left (b^{3} c - 4 \, a b c^{2}\right )} x}{2 \, {\left (b^{6} c^{2} - 12 \, a b^{4} c^{3} + 48 \, a^{2} b^{2} c^{4} - 64 \, a^{3} c^{5}\right )} d^{2} x^{3} + 3 \, {\left (b^{7} c - 12 \, a b^{5} c^{2} + 48 \, a^{2} b^{3} c^{3} - 64 \, a^{3} b c^{4}\right )} d^{2} x^{2} + {\left (b^{8} - 10 \, a b^{6} c + 24 \, a^{2} b^{4} c^{2} + 32 \, a^{3} b^{2} c^{3} - 128 \, a^{4} c^{4}\right )} d^{2} x + {\left (a b^{7} - 12 \, a^{2} b^{5} c + 48 \, a^{3} b^{3} c^{2} - 64 \, a^{4} b c^{3}\right )} d^{2}}, -\frac {b^{4} + 4 \, a b^{2} c - 32 \, a^{2} c^{2} + 12 \, {\left (b^{2} c^{2} - 4 \, a c^{3}\right )} x^{2} - 12 \, {\left (2 \, c^{3} x^{3} + 3 \, b c^{2} x^{2} + a b c + {\left (b^{2} c + 2 \, a c^{2}\right )} x\right )} \sqrt {-b^{2} + 4 \, a c} \arctan \left (-\frac {\sqrt {-b^{2} + 4 \, a c} {\left (2 \, c x + b\right )}}{b^{2} - 4 \, a c}\right ) + 12 \, {\left (b^{3} c - 4 \, a b c^{2}\right )} x}{2 \, {\left (b^{6} c^{2} - 12 \, a b^{4} c^{3} + 48 \, a^{2} b^{2} c^{4} - 64 \, a^{3} c^{5}\right )} d^{2} x^{3} + 3 \, {\left (b^{7} c - 12 \, a b^{5} c^{2} + 48 \, a^{2} b^{3} c^{3} - 64 \, a^{3} b c^{4}\right )} d^{2} x^{2} + {\left (b^{8} - 10 \, a b^{6} c + 24 \, a^{2} b^{4} c^{2} + 32 \, a^{3} b^{2} c^{3} - 128 \, a^{4} c^{4}\right )} d^{2} x + {\left (a b^{7} - 12 \, a^{2} b^{5} c + 48 \, a^{3} b^{3} c^{2} - 64 \, a^{4} b c^{3}\right )} d^{2}}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.17, size = 220, normalized size = 2.24 \begin {gather*} -\frac {8 \, c^{5} d^{7}}{{\left (b^{4} c^{4} d^{8} - 8 \, a b^{2} c^{5} d^{8} + 16 \, a^{2} c^{6} d^{8}\right )} {\left (2 \, c d x + b d\right )}} - \frac {12 \, c \arctan \left (\frac {\frac {b^{2} d}{2 \, c d x + b d} - \frac {4 \, a c d}{2 \, c d x + b d}}{\sqrt {-b^{2} + 4 \, a c}}\right )}{{\left (b^{4} - 8 \, a b^{2} c + 16 \, a^{2} c^{2}\right )} \sqrt {-b^{2} + 4 \, a c} d^{2}} + \frac {4 \, c}{{\left (b^{4} - 8 \, a b^{2} c + 16 \, a^{2} c^{2}\right )} {\left (2 \, c d x + b d\right )} {\left (\frac {b^{2} d^{2}}{{\left (2 \, c d x + b d\right )}^{2}} - \frac {4 \, a c d^{2}}{{\left (2 \, c d x + b d\right )}^{2}} - 1\right )} d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.06, size = 127, normalized size = 1.30 \begin {gather*} -\frac {2 c x}{\left (4 a c -b^{2}\right )^{2} \left (c \,x^{2}+b x +a \right ) d^{2}}-\frac {12 c \arctan \left (\frac {2 c x +b}{\sqrt {4 a c -b^{2}}}\right )}{\left (4 a c -b^{2}\right )^{\frac {5}{2}} d^{2}}-\frac {b}{\left (4 a c -b^{2}\right )^{2} \left (c \,x^{2}+b x +a \right ) d^{2}}-\frac {8 c}{\left (4 a c -b^{2}\right )^{2} \left (2 c x +b \right ) d^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.65, size = 232, normalized size = 2.37 \begin {gather*} -\frac {\frac {b^2+8\,a\,c}{{\left (4\,a\,c-b^2\right )}^2}+\frac {12\,c^2\,x^2}{{\left (4\,a\,c-b^2\right )}^2}+\frac {12\,b\,c\,x}{{\left (4\,a\,c-b^2\right )}^2}}{x\,\left (b^2\,d^2+2\,a\,c\,d^2\right )+2\,c^2\,d^2\,x^3+a\,b\,d^2+3\,b\,c\,d^2\,x^2}-\frac {12\,c\,\mathrm {atan}\left (\frac {\frac {6\,c\,\left (16\,a^2\,b\,c^2\,d^2-8\,a\,b^3\,c\,d^2+b^5\,d^2\right )}{d^2\,{\left (4\,a\,c-b^2\right )}^{5/2}}+\frac {12\,c^2\,x\,\left (16\,a^2\,c^2\,d^2-8\,a\,b^2\,c\,d^2+b^4\,d^2\right )}{d^2\,{\left (4\,a\,c-b^2\right )}^{5/2}}}{6\,c}\right )}{d^2\,{\left (4\,a\,c-b^2\right )}^{5/2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [B] time = 1.89, size = 459, normalized size = 4.68 \begin {gather*} \frac {6 c \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{5}}} \log {\left (x + \frac {- 384 a^{3} c^{4} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{5}}} + 288 a^{2} b^{2} c^{3} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{5}}} - 72 a b^{4} c^{2} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{5}}} + 6 b^{6} c \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{5}}} + 6 b c}{12 c^{2}} \right )}}{d^{2}} - \frac {6 c \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{5}}} \log {\left (x + \frac {384 a^{3} c^{4} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{5}}} - 288 a^{2} b^{2} c^{3} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{5}}} + 72 a b^{4} c^{2} \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{5}}} - 6 b^{6} c \sqrt {- \frac {1}{\left (4 a c - b^{2}\right )^{5}}} + 6 b c}{12 c^{2}} \right )}}{d^{2}} + \frac {- 8 a c - b^{2} - 12 b c x - 12 c^{2} x^{2}}{16 a^{3} b c^{2} d^{2} - 8 a^{2} b^{3} c d^{2} + a b^{5} d^{2} + x^{3} \left (32 a^{2} c^{4} d^{2} - 16 a b^{2} c^{3} d^{2} + 2 b^{4} c^{2} d^{2}\right ) + x^{2} \left (48 a^{2} b c^{3} d^{2} - 24 a b^{3} c^{2} d^{2} + 3 b^{5} c d^{2}\right ) + x \left (32 a^{3} c^{3} d^{2} - 6 a b^{4} c d^{2} + b^{6} d^{2}\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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